The partial pressure of oxygen at ((A)) and blood capillary of lungs ((B)) will be :

Options

A. A : 104 mm Hg , B : 95 mm Hg
B. A : 159 mm Hg , B : 95 mm Hg
C. A : 104 mm Hg , B : 40 mm Hg
D. A : 159 mm Hg , B : 95 mm Hg

Answer

To solve the question regarding the partial pressure of oxygen at point A and in the blood capillary of the lungs (point B), we will analyze the information provided in the video transcript step by step.

### Step-by-Step Solution:

1. **Understanding Partial Pressure**:
- Partial pressure refers to the pressure exerted by a specific gas in a mixture of gases. In this case, we are focusing on the partial pressure of oxygen (O2).

2. **Identifying Point A**:
- The transcript mentions that the partial pressure of oxygen in the alveolar air (which can be considered as point A) is 104 mm Hg. This is the pressure of oxygen in the air within the lungs.

3. **Identifying Point B**:
- The transcript states that the partial pressure of oxygen in the oxygenated blood (which can be considered as point B) is 95 mm Hg. This is the pressure of oxygen in the blood after it has been oxygenated in the lungs.

4. **Conclusion**:
- Therefore, the partial pressures of oxygen at points A and B are:
- A (Alveolar air) = 104 mm Hg
- B (Blood capillary of lungs) = 95 mm Hg

5. **Final Answer**:
- The correct answer to the question is:
- A = 104 mm Hg, B = 95 mm Hg.