How many meiotic divisions are required to produce 104 male gametes in a typical Angiospermic plant ?

Options

A. 25
B. 26
C. 51
D. 13

Answer

To determine how many meiotic divisions are required to produce 104 male gametes in a typical Angiospermic plant, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Process**: In angiospermic plants, the microspore mother cell (microsporocyte) undergoes meiosis to produce microspores. Each microspore can then undergo mitotic divisions to produce male gametes (pollen grains).

2. **Meiotic Division**: Each microspore mother cell undergoes one meiotic division, resulting in four microspores.

3. **Mitotic Division**: Each microspore undergoes two mitotic divisions to produce two male gametes. Therefore, from one microspore, we can get a total of 2 male gametes.

4. **Calculating Total Male Gametes from Meiotic Divisions**:
- From one microspore mother cell (1 meiotic division), we get 4 microspores.
- Each of these 4 microspores undergoes 2 mitotic divisions, resulting in:
- 4 microspores × 2 male gametes/microspore = 8 male gametes from one meiotic division.

5. **Finding the Number of Meiotic Divisions for 104 Male Gametes**:
- To find how many meiotic divisions are needed to produce 104 male gametes, we can set up the equation:
- Total male gametes = Number of meiotic divisions × 8 male gametes.
- Therefore, we need to solve for the number of meiotic divisions:
- 104 male gametes ÷ 8 male gametes/meiotic division = 13 meiotic divisions.

6. **Conclusion**: Thus, the number of meiotic divisions required to produce 104 male gametes is 13.

### Final Answer:
The answer is option **d) 13**.

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