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Two parents having two loci incompletely...

Two parents having two loci incompletely linked and heterozygous in nature are crossed. What would be the distribution of phenotypic feature in the `F_2` generation ?

A

Only parental phenotype

B

Only recombinant phenotype

C

High parental and low recombinant phenotype

D

Low parental and high recombinant phenotype

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the distribution of phenotypic features in the F2 generation from two parents with incompletely linked loci that are heterozygous, we can follow these steps: ### Step 1: Understand the Genotypes of the Parents The two parents are heterozygous for two loci, which can be represented as: - Parent 1: AABB (where A and B are dominant alleles) - Parent 2: aabb (where a and b are recessive alleles) ### Step 2: Determine the Gametes Produced by Each Parent Since both parents are heterozygous, they can produce the following gametes: - Parent 1 (AABB): Can produce gametes AB and ab - Parent 2 (aabb): Can produce gametes ab ### Step 3: Perform the F1 Generation Cross When the two parents are crossed, the F1 generation will all be heterozygous: - F1 Generation: AaBb ### Step 4: Analyze the F2 Generation To find the F2 generation, we need to cross the F1 individuals (AaBb x AaBb). The possible gametes from each F1 individual are: - Gametes: AB, Ab, aB, ab ### Step 5: Set Up a Punnett Square Using a Punnett square, we can determine the combinations of these gametes: ``` AB Ab aB ab -------------------------------- AB | AABB | AABb | AaBB | AaBb | -------------------------------- Ab | AABb | AAbb | AaBb | Aabb | -------------------------------- aB | AaBB | AaBb | aaBB | aaBb | -------------------------------- ab | AaBb | Aabb | aaBb | aabb | ``` ### Step 6: Count the Phenotypes Now we can count the phenotypes based on the combinations: - Parental types (AABB, AAbb, aaBB, aabb): 4 - Recombinant types (AABb, AaBB, AaBb, Aabb, aaBb): 6 ### Step 7: Determine the Phenotypic Ratio In the F2 generation, we expect a higher number of parental phenotypes compared to recombinant phenotypes due to the incomplete linkage: - Parental phenotypes: 4 - Recombinant phenotypes: 6 ### Conclusion The distribution of phenotypic features in the F2 generation will show a higher frequency of parental phenotypes compared to recombinant phenotypes due to the incomplete linkage of the genes.
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