What will be DNA amount in Meiotic II products if DNA is 20 picogram in meiocyte at `G_(2)` stage ?

Options

A. 5 pg
B. 10 pg
C. 20 pg
D. 40 pg

Answer

To solve the problem, we need to understand the process of meiosis and how DNA content changes during this process. Here's a step-by-step breakdown:

### Step 1: Understand the DNA content at G2 stage
- At the G2 stage, the DNA content in the meiocyte is given as 20 picograms. This is the amount of DNA present after the S phase of the cell cycle, where DNA replication occurs.

**Hint:** Remember that during the S phase, DNA is replicated, doubling the amount of DNA.

### Step 2: DNA content after Meiosis I
- During Meiosis I, the cell divides into two daughter cells. The DNA content is halved because homologous chromosomes are separated.
- Since the initial amount of DNA was 20 picograms, after Meiosis I, each daughter cell will have:
\[ \text{DNA in each cell after Meiosis I} = \frac{20 \text{ picograms}}{2} = 10 \text{ picograms} \]

**Hint:** In Meiosis I, homologous chromosomes separate, which reduces the DNA content by half.

### Step 3: DNA content after Meiosis II
- Meiosis II is similar to mitosis, where the two daughter cells from Meiosis I divide again. However, there is no further DNA replication before this division.
- Each of the two cells from Meiosis I will divide to form a total of four haploid cells. The DNA content in each of these cells remains the same as in the cells after Meiosis I:
\[ \text{DNA in each cell after Meiosis II} = 10 \text{ picograms} \]

**Hint:** Meiosis II does not involve DNA replication; it only separates sister chromatids.

### Conclusion
- Therefore, the amount of DNA in each of the four products of Meiosis II will be 10 picograms.

**Final Answer:** The DNA amount in Meiotic II products will be **10 picograms**.