The different gametes produced by an invidual with the genotype of aaBBCc are .

Options

A. 2
B. 8
C. 4
D. 6

Answer

To determine the different gametes produced by an individual with the genotype aaBBCc, we can follow these steps:

### Step 1: Identify the Genotype
The given genotype is:
- aa (homozygous recessive)
- BB (homozygous dominant)
- Cc (heterozygous)

### Step 2: Determine Heterozygous Alleles
In the genotype, we need to identify the heterozygous alleles. Here, we have:
- Cc is the only heterozygous pair.

### Step 3: Count the Number of Heterozygous Alleles
Since there is only one heterozygous pair (Cc), we have:
- Number of heterozygous pairs (n) = 1

### Step 4: Use the Formula for Gamete Production
The formula to calculate the number of different gametes produced is:
\[ \text{Number of different gametes} = 2^n \]
Where \( n \) is the number of heterozygous pairs.

### Step 5: Calculate the Number of Gametes
Substituting the value of \( n \):
\[ \text{Number of different gametes} = 2^1 = 2 \]

### Step 6: List the Possible Gametes
The possible gametes produced from the genotype aaBBCc are:
1. aB C
2. aB c

### Conclusion
Therefore, the different gametes produced by an individual with the genotype aaBBCc are 2.

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