Saccharin is imide of

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Answer

To determine the imide of saccharin, we need to analyze the structure of saccharin and identify the compound from which it is derived. Here is the step-by-step solution:

### Step 1: Identify the Structure of Saccharin
Saccharin is a synthetic sweetening agent. Its chemical structure includes a benzene ring, a sulfonyl group (SO3H), and an amide group (NH).

### Step 2: Recognize the Functional Groups
In the structure of saccharin, we can identify:
- A benzene ring (C6H4)
- A sulfonyl group (SO2)
- An amide group (NH)

### Step 3: Determine the Parent Compound
The imide of saccharin can be derived from ortho-sulfobenzoic acid. This compound has a sulfonyl group attached to the benzene ring at the ortho position relative to the carboxylic acid group.

### Step 4: Form the Imide
To form the imide, we need to remove one hydrogen from the amide group (NH) and one hydroxyl group (OH) from the carboxylic acid (COOH) of ortho-sulfobenzoic acid. This results in the formation of the imide linkage.

### Step 5: Conclusion
The imide of saccharin is derived from ortho-sulfobenzoic acid. Thus, saccharin is the imide of ortho-sulfobenzoic acid.

### Final Answer
Saccharin is the imide of ortho-sulfobenzoic acid.

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