Home
Class 12
CHEMISTRY
The equilibrium constant for the reactio...

The equilibrium constant for the reaction `Br_(2)hArr2Br "at" 500 K "and" 700 K "are" 1xx10^(-5)` respectively. The reaction is:

A

endothermic

B

exothermic

C

fast

D

slow

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The equilibrium constants for the reaction Br_(2)hArr 2Br at 500 K and 700 K are 1xx10^(-10) and 1xx10^(-5) respectively. The reaction is:

The equilibrium constants for the reaction Br_(2)hArr 2Br at 500 K and 700 K are 1xx10^(-10) and 1xx10^(-5) respectively. The reaction is:

The equilibrium constants for the reaction, A_2hArr2A A at 500K and 700K are 1xx10^(-10) and 1xx10^(-5) . The given reaction is

The equilibrium constants for A_2 (g) hArr 2A(g) at 400 k and 600 k are 1xx 10^(-8) and 1 xx 10^(-2) respectively . The reaction is

The unit of equilibrium constant K_(c) for the reaction A+B hArr C would be

The equilibrium constant for the reaction H_(2)(g)+S(s) hArr H_(2)S(g) is 18.5 at 925 K and 9.25 at 1000 K , respectively. Calculate the enthalpy of the reaction.

The equilibrium constant for the reaction A(g)hArrB(g) and B(g)hArrC(g) are K_1=10^(-2) and K_2=10^(-1) respectively . Equilibrium constant for the reaction (1/2)C(g)hArr(1/2)A(g) is

The equilibrium constant for the reactions N_(2)+O_(2)hArr2NO"and "NO+1/2O_(2)hArrNO_(2)"are"K_(1)"and"K_(2) respectively, that will be the equilibrium constant for the reaction

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant for the reaction H_(2)+Br_(2)hArr2HBr is 67.8 at 300 K . The equilibrium constant for the dissociation of HBr is: