In which reaction the product is not correctly given ?

Options

A. `PhOCH_3+Br_(2)overset(FeBr_3)(rarr)p-BrPhOCH_3`
B. `PhCOOH+CH_3CH_2Cloverset(AlCl_3)(rarr)p-C_2H_5PhCOOH`
C.
D. Both A and B

Answer

To solve the question, we need to analyze each of the given reactions and determine if the products are correctly stated.

### Step-by-Step Solution:

1. **Analyze the First Reaction:**
- The first reaction involves anisole (methoxybenzene) reacting with bromine in the presence of ferric bromide (FeBr3).
- Anisole has a methoxy group (-OCH3) which is an ortho-para directing and activating group.
- The reaction will yield both ortho and para bromoanisole, with para-bromoanisole being the major product.
- **Conclusion:** The product is correctly given as para-bromoanisole.

2. **Analyze the Second Reaction:**
- The second reaction involves the Friedel-Crafts reaction of benzoic acid.
- Benzoic acid contains a carboxylic acid group (-COOH), which is a deactivating group and withdraws electron density from the aromatic ring.
- Due to this deactivation, benzoic acid does not undergo Friedel-Crafts alkylation or acylation reactions.
- **Conclusion:** The product is incorrectly given because benzoic acid cannot undergo Friedel-Crafts reactions.

3. **Analyze the Third Reaction:**
- The third reaction involves isopropylbenzene (cumene) being oxidized with potassium permanganate (KMnO4).
- Isopropylbenzene has an alpha hydrogen, and upon oxidation, the side chain will be oxidized to a carboxylic acid (benzoic acid).
- **Conclusion:** The product is correctly given as benzoic acid.

### Final Conclusion:
- The reaction where the product is not correctly given is the **second reaction** involving benzoic acid and Friedel-Crafts reaction.