The product of Reimer-Tiemann reaction is a

Options

A. Carbonium ion intermediate
B. Carbene intermediate
C. Carbanion intermediate
D. Free radical intermediate

Answer

To solve the question regarding the product of the Reimer-Tiemann reaction, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Reimer-Tiemann Reaction**:
The Reimer-Tiemann reaction is a chemical reaction that involves the ortho-formylation of phenols using chloroform (CHCl3) in the presence of a strong base, typically potassium hydroxide (KOH).

**Hint**: Recall that the Reimer-Tiemann reaction specifically targets phenols and leads to the formation of aldehydes.

2. **Identify the Reactants**:
The main reactants in the Reimer-Tiemann reaction are phenol (C6H5OH), chloroform (CHCl3), and a strong base like KOH.

**Hint**: Focus on the role of each reactant in the reaction mechanism.

3. **Mechanism Overview**:
- The KOH deprotonates the phenol, generating a phenoxide ion (C6H5O⁻).
- The phenoxide ion then reacts with chloroform (CHCl3). The KOH also helps in generating a dichlorocarbene intermediate (CCl2) from chloroform.

**Hint**: Think about how the strong base facilitates the formation of reactive intermediates.

4. **Formation of the Product**:
The generated dichlorocarbene (CCl2) reacts with the phenoxide ion, leading to the formation of ortho-hydroxybenzaldehyde (C6H4(OH)CHO) as the main product.

**Hint**: Remember that the reaction favors the ortho position due to steric and electronic effects.

5. **Final Product Identification**:
The final product of the Reimer-Tiemann reaction is ortho-hydroxybenzaldehyde, which can also be referred to as salicylaldehyde.

**Hint**: Confirm the structure of the product by drawing it out or visualizing the reaction outcome.

### Conclusion:
The product of the Reimer-Tiemann reaction is ortho-hydroxybenzaldehyde (salicylaldehyde).