`XeO_4` molecule is tetrahedral having 'n' number of `p pi - d pi` bonds. The value of 'n' is

Options

A. 1
B. 2
C. 3
D. 4

Answer

To determine the number of pπ-dπ bonds in the molecule \( \text{XeO}_4 \), we can follow these steps:

### Step 1: Understand the Structure of \( \text{XeO}_4 \)
- The molecule \( \text{XeO}_4 \) consists of one xenon (Xe) atom and four oxygen (O) atoms.
- In \( \text{XeO}_4 \), xenon is the central atom, and it forms double bonds with each of the four oxygen atoms.

### Step 2: Identify the Bonding
- Each double bond between xenon and oxygen consists of one sigma bond and one pi bond.
- The pi bonds are formed by the overlap of p orbitals from oxygen and the vacant d orbitals from xenon.

### Step 3: Count the Number of pπ-dπ Bonds
- Since there are four oxygen atoms, and each oxygen forms a double bond with xenon, there will be four pi bonds.
- Each of these pi bonds can be classified as a pπ-dπ bond because they involve the p orbitals of oxygen and the d orbitals of xenon.

### Conclusion
- Therefore, the total number of pπ-dπ bonds (denoted as 'n') in \( \text{XeO}_4 \) is 4.

The value of 'n' is **4**.

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