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A compound contains 28% N and 72% of a m...

A compound contains 28% N and 72% of a metal by weight . Three atoms of metal combine with two atoms of N . Find the atomic weight of metal.

A

12

B

32

C

24

D

16

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the composition of the compound The compound contains: - 28% Nitrogen (N) - 72% Metal (M) ### Step 2: Determine the total weight of the compound Assuming we have 100 grams of the compound, we can directly use the percentages to find the weights: - Weight of Nitrogen = 28 grams - Weight of Metal = 72 grams ### Step 3: Establish the relationship between the atoms According to the problem, 3 atoms of Metal combine with 2 atoms of Nitrogen. This gives us a ratio of: - 3 M : 2 N ### Step 4: Calculate the weight of Nitrogen in the compound The atomic weight of Nitrogen (N) is approximately 14 g/mol. Therefore, the weight of 2 nitrogen atoms is: - Weight of 2 N = 2 × 14 g = 28 grams ### Step 5: Calculate the weight of Metal in the compound From the total weight of the compound, we know that the weight of 3 metal atoms is: - Weight of 3 M = 72 grams ### Step 6: Find the weight of one metal atom To find the weight of one metal atom, we divide the total weight of the metal by the number of metal atoms: - Weight of 1 M = Weight of 3 M / 3 = 72 grams / 3 = 24 grams ### Step 7: Conclusion The atomic weight of the metal is 24 grams. ### Final Answer The atomic weight of the metal is **24 g/mol**. ---
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