The number of waves made by a Bohr electron in an orbit of maximum magnetic quantum number + 2 is

Options

A. 3
B. 0
C. 2
D. 1

Answer

To solve the question regarding the number of waves made by a Bohr electron in an orbit with a maximum magnetic quantum number of +2, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Quantum Numbers**:
- The magnetic quantum number (m_l) can take values from -l to +l, where l is the azimuthal quantum number (orbital angular momentum quantum number).
- The azimuthal quantum number (l) can take values from 0 to n-1, where n is the principal quantum number.

2. **Identify the Given Magnetic Quantum Number**:
- The problem states that the magnetic quantum number (m_l) is +2.

3. **Determine the Possible Values of l**:
- Since m_l = +2, the possible values of l must be at least 2 (because m_l can take values from -l to +l).
- Therefore, the minimum value of l is 2.

4. **Determine the Principal Quantum Number (n)**:
- For a given value of l, the principal quantum number n must be greater than l (n > l).
- Since l = 2, the smallest possible value for n is 3 (n = l + 1).

5. **Calculate the Number of Waves**:
- The number of waves made by a Bohr electron in an orbit corresponds to the principal quantum number n.
- Since we found that n = 3, the number of waves made by the electron is 3.

### Final Answer:
The number of waves made by a Bohr electron in an orbit with a maximum magnetic quantum number of +2 is **3**.

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