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For an ideal binary liquid solution with...

For an ideal binary liquid solution with `p_(A)^(@) gt p_(B)^(@),` which is a relation between `X_(A)` (mole fraction of A in liquid phase) and `Y_(A)` (mole fraction of A in vapour phase) is correct, `X_(B) and Y_(B)` are mole fractions of B in liquid and vapour phase respectively?

A

`X_A = Y_A`

B

`X_A gt Y_A`

C

`(X_A)/(X_B) lt (Y_A)/(Y_B)`

D

`X_A, Y_A, X_B and Y_B` cannot be correlated

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between the mole fractions of components A and B in both the liquid and vapor phases of an ideal binary liquid solution, given that the vapor pressure of A (P₀A) is greater than that of B (P₀B). ### Step-by-Step Solution: 1. **Understanding the Given Information**: - We have a binary liquid solution with components A and B. - The vapor pressure of A (P₀A) is greater than the vapor pressure of B (P₀B), i.e., P₀A > P₀B. 2. **Applying Raoult's Law**: - According to Raoult's Law, the partial pressure of each component in the vapor phase can be expressed as: - \( P_A = P_0A \cdot X_A \) (for component A) - \( P_B = P_0B \cdot X_B \) (for component B) - Where \( X_A \) and \( X_B \) are the mole fractions of A and B in the liquid phase, respectively. 3. **Total Pressure in the System**: - The total pressure (P_T) of the system is the sum of the partial pressures: \[ P_T = P_A + P_B = P_0A \cdot X_A + P_0B \cdot X_B \] 4. **Relating Mole Fractions in Vapor Phase**: - The mole fractions of A and B in the vapor phase can be expressed as: - \( Y_A = \frac{P_A}{P_T} \) - \( Y_B = \frac{P_B}{P_T} \) 5. **Substituting for Partial Pressures**: - Substituting the expressions for \( P_A \) and \( P_B \) into the equations for \( Y_A \) and \( Y_B \): \[ Y_A = \frac{P_0A \cdot X_A}{P_0A \cdot X_A + P_0B \cdot X_B} \] \[ Y_B = \frac{P_0B \cdot X_B}{P_0A \cdot X_A + P_0B \cdot X_B} \] 6. **Setting Up the Ratio**: - We can set up the ratio of the mole fractions: \[ \frac{Y_A}{Y_B} = \frac{P_0A \cdot X_A}{P_0B \cdot X_B} \] - Given that \( P_0A > P_0B \), this implies that: \[ \frac{Y_A}{Y_B} > \frac{X_A}{X_B} \] 7. **Conclusion**: - Rearranging gives us the relationship: \[ \frac{X_A}{X_B} < \frac{Y_A}{Y_B} \] - This indicates that the mole fraction of A in the liquid phase is less than the mole fraction of A in the vapor phase, which is consistent with the fact that A has a higher vapor pressure than B. ### Final Answer: The correct relationship is: \[ \frac{X_A}{X_B} < \frac{Y_A}{Y_B} \]
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