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Free radical chlorination of hexane prod...

Free radical chlorination of hexane produces how many of monochloro derivatives? (including stereoisomer)

A

5

B

7

C

8

D

3

Text Solution

AI Generated Solution

The correct Answer is:
To determine how many monochloro derivatives can be produced from the free radical chlorination of hexane, we will follow these steps: ### Step 1: Identify the Structure of Hexane Hexane is a straight-chain alkane with the formula C6H14. Its structure can be represented as: \[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_3 \] ### Step 2: Identify Equivalent Carbons In hexane, we have: - 2 equivalent carbons at the ends (C1 and C6) - 2 equivalent carbons in the middle (C2 and C5) - 2 equivalent carbons in the middle (C3 and C4) This gives us three distinct types of hydrogen atoms that can be replaced by chlorine: 1. Primary (C1 and C6) 2. Secondary (C2 and C5) 3. Tertiary (C3 and C4) ### Step 3: Determine the Number of Structural Isomers When chlorination occurs, we can replace one hydrogen atom with a chlorine atom at each of these equivalent positions: - Replacing a hydrogen from C1 or C6 gives us one type of monochloro derivative. - Replacing a hydrogen from C2 or C5 gives us another type of monochloro derivative. - Replacing a hydrogen from C3 or C4 gives us a third type of monochloro derivative. Thus, we have three different structural isomers: 1. 1-chlorohexane (from C1 or C6) 2. 2-chlorohexane (from C2 or C5) 3. 3-chlorohexane (from C3 or C4) ### Step 4: Identify Chiral Centers Next, we need to check for chiral centers among these isomers: - **1-chlorohexane**: No chiral center. - **2-chlorohexane**: Has one chiral center (C2), leading to two optical isomers (R and S). - **3-chlorohexane**: Has one chiral center (C3), leading to two optical isomers (R and S). ### Step 5: Count Total Monochloro Derivatives Now, we can summarize the total number of monochloro derivatives: - Structural isomers: 3 (1-chlorohexane, 2-chlorohexane, 3-chlorohexane) - Optical isomers: - 2 for 2-chlorohexane (R and S) - 2 for 3-chlorohexane (R and S) Thus, the total number of monochloro derivatives is: \[ 1 \text{ (from 1-chloro)} + 2 \text{ (from 2-chloro)} + 2 \text{ (from 3-chloro)} = 5 \] ### Final Answer The total number of monochloro derivatives of hexane, including stereoisomers, is **5**. ---
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