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An inorganic compounds gives off O2 on h...

An inorganic compounds gives off `O_2` on heating. It also makes the colourless solution of potassium iodide to acquire purple tinge. The compound can be

A

`SO_3`

B

`K_2CO_3`

C

`H_2O_2`

D

`H_2O`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to identify an inorganic compound that meets the following criteria: 1. It gives off \( O_2 \) when heated. 2. It causes a colorless solution of potassium iodide (KI) to acquire a purple tinge. Let's analyze the problem step by step: ### Step 1: Identify the decomposition reaction We need a compound that releases \( O_2 \) upon heating. A well-known compound that fits this description is hydrogen peroxide (\( H_2O_2 \)). **Hint:** Look for compounds known for releasing oxygen upon thermal decomposition. ### Step 2: Write the decomposition reaction When hydrogen peroxide is heated, it decomposes as follows: \[ 2 H_2O_2 \rightarrow 2 H_2O + O_2 \] This reaction confirms that \( H_2O_2 \) produces \( O_2 \) gas upon heating. **Hint:** Consider the common thermal decomposition reactions of known compounds. ### Step 3: Check the reaction with potassium iodide Next, we need to check how \( H_2O_2 \) interacts with potassium iodide. When \( H_2O_2 \) is added to a colorless solution of potassium iodide, it oxidizes iodide ions (\( I^- \)) to iodine (\( I_2 \)), which imparts a purple color to the solution: \[ H_2O_2 + 2 KI \rightarrow I_2 + 2 KOH \] The iodine (\( I_2 \)) produced is responsible for the purple tinge. **Hint:** Consider the oxidation-reduction reactions involving iodine and iodide ions. ### Step 4: Conclusion Since both conditions of the question are satisfied by hydrogen peroxide (\( H_2O_2 \)), we conclude that the compound in question is: \[ \text{Hydrogen peroxide (} H_2O_2\text{)} \] **Final Answer:** The compound can be \( H_2O_2 \).
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