The percentage of oxygen in `CH_(2) O` is

Options

A. `40%`
B. `6.6%`
C. `53.33%`
D. `49%`

Answer

To find the percentage of oxygen in the compound CH₂O, we will follow these steps:

### Step 1: Calculate the molar mass of CH₂O
- Carbon (C) has an atomic mass of 12 g/mol.
- Hydrogen (H) has an atomic mass of 1 g/mol, and there are 2 hydrogen atoms in CH₂O, so the contribution from hydrogen is \(2 \times 1 = 2\) g/mol.
- Oxygen (O) has an atomic mass of 16 g/mol.

Now, we can calculate the total molar mass of CH₂O:
\[ \text{Molar mass of CH₂O} = \text{Molar mass of C} + \text{Molar mass of H} + \text{Molar mass of O} \]
\[ = 12 + 2 + 16 = 30 \text{ g/mol} \]

### Step 2: Calculate the mass percentage of oxygen in CH₂O
To find the percentage of oxygen, we use the formula:
\[ \text{Percentage of oxygen} = \left( \frac{\text{Mass of oxygen}}{\text{Molar mass of CH₂O}} \right) \times 100 \]
Substituting the values we have:
\[ \text{Percentage of oxygen} = \left( \frac{16}{30} \right) \times 100 \]

### Step 3: Simplify the calculation
Calculating the fraction:
\[ \frac{16}{30} = 0.5333 \]
Now, multiplying by 100 to get the percentage:
\[ 0.5333 \times 100 = 53.33\% \]

### Conclusion
The percentage of oxygen in CH₂O is **53.33%**.

### Final Answer
Thus, the correct option is **C**.

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