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A compound contains three elements X, Y ...

A compound contains three elements X, Y and Z. The oxidation number of X, Y and Z are `+3, +5 and -2` respectively. The possible formula of the compound is

A

`X_(2)YZ`

B

`XYZ_(3)`

C

`X_(3)(YZ_(4))_(3)`

D

`X_(2)Y_(2)Z`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the possible formula of the compound containing elements X, Y, and Z with oxidation states +3, +5, and -2 respectively, we can follow these steps: ### Step 1: Understand the oxidation states - The oxidation states of the elements are: - X: +3 - Y: +5 - Z: -2 ### Step 2: Set up the equation for neutrality - For a compound to be neutral, the sum of the oxidation states multiplied by their respective subscripts must equal zero. We can express this as: \[ x(\text{oxidation state of X}) + y(\text{oxidation state of Y}) + z(\text{oxidation state of Z}) = 0 \] Where \( x, y, z \) are the subscripts for elements X, Y, and Z respectively. ### Step 3: Analyze the options We will analyze the given options one by one to find a valid formula. #### Option A: \( X_2Y_1Z_1 \) - Calculation: \[ 2(+3) + 1(+5) + 1(-2) = 6 + 5 - 2 = 9 \quad (\text{not equal to } 0) \] - This option is not valid. #### Option B: \( XY_1Z_1 \) - Calculation: \[ 1(+3) + 1(+5) + 1(-2) = 3 + 5 - 2 = 6 \quad (\text{not equal to } 0) \] - This option is not valid. #### Option C: \( X_3Y_1Z_4 \) - Calculation: \[ 3(+3) + 1(+5) + 4(-2) = 9 + 5 - 8 = 6 \quad (\text{not equal to } 0) \] - This option is not valid. #### Option D: \( X_2Y_2Z_1 \) - Calculation: \[ 2(+3) + 2(+5) + 1(-2) = 6 + 10 - 2 = 14 \quad (\text{not equal to } 0) \] - This option is not valid. ### Step 4: Re-evaluate the calculations After analyzing all options, we realize that none of the options provided yield a neutral compound. However, we can derive a possible formula based on the oxidation states. ### Step 5: Find a suitable combination To achieve neutrality, we can try: Let \( x = 1 \), \( y = 1 \), \( z = 3 \): \[ 1(+3) + 1(+5) + 3(-2) = 3 + 5 - 6 = 2 \quad (\text{not equal to } 0) \] Let \( x = 2 \), \( y = 1 \), \( z = 3 \): \[ 2(+3) + 1(+5) + 3(-2) = 6 + 5 - 6 = 5 \quad (\text{not equal to } 0) \] Let \( x = 3 \), \( y = 1 \), \( z = 4 \): \[ 3(+3) + 1(+5) + 4(-2) = 9 + 5 - 8 = 6 \quad (\text{not equal to } 0) \] Let \( x = 1 \), \( y = 2 \), \( z = 3 \): \[ 1(+3) + 2(+5) + 3(-2) = 3 + 10 - 6 = 7 \quad (\text{not equal to } 0) \] ### Conclusion After evaluating the options and trying various combinations, it appears that the correct formula for the compound cannot be determined from the provided options. However, based on the oxidation states, a possible neutral formula could be derived as \( X_2Y_1Z_3 \) or similar combinations that yield a sum of zero.
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