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In borax number of B-O-B bonds are X and...

In borax number of `B-O-B` bonds are X and number of boron atoms are Y. Then `X+Y` is

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To solve the problem, we need to determine the number of `B-O-B` bonds (denoted as X) and the number of boron atoms (denoted as Y) in the compound borax, which has the chemical formula Na2B4O7·10H2O. ### Step-by-Step Solution: 1. **Identify the Chemical Formula**: The formula for borax is Na2B4O7·10H2O. This indicates that borax contains boron (B), oxygen (O), and sodium (Na). 2. **Count the Boron Atoms (Y)**: From the formula, we can see that there are 4 boron atoms (B). Therefore, Y = 4. 3. **Understand the Structure of Borax**: Borax has a specific structure where boron atoms are connected through oxygen atoms. The `B-O-B` bonds are formed between boron atoms. 4. **Count the B-O-B Bonds (X)**: In the structure of borax, we can visualize that there are 5 `B-O-B` bonds. This is because: - Each of the 4 boron atoms is connected to at least one other boron atom through an oxygen atom. - The arrangement of boron atoms leads to a total of 5 such bonds. 5. **Calculate X + Y**: Now that we have X = 5 (the number of `B-O-B` bonds) and Y = 4 (the number of boron atoms), we can calculate: \[ X + Y = 5 + 4 = 9 \] ### Final Answer: Thus, the value of \( X + Y \) is **9**.
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