The number of stereo isomers possible for a compound of the molecular formula is `CH_(3)-CH=CH-CH(NH_(2))-CH_(3)` is

Answer

To determine the number of stereoisomers for the compound with the molecular formula CH₃-CH=CH-CH(NH₂)-CH₃, we need to analyze the structure and identify the stereocenters.

### Step 1: Identify the Structure
The given molecular formula can be represented as follows:
- The compound has a straight-chain structure with a double bond (alkene) and an amine group (NH₂) attached to one of the carbon atoms.

### Step 2: Identify Stereocenters
1. **Chiral Center**: The carbon atom that is bonded to four different groups is a chiral center. In this case, the carbon attached to the NH₂ group is a chiral center.
2. **Geometric Isomerism**: The double bond between the second and third carbon atoms can also give rise to geometric isomers (cis and trans forms).

### Step 3: Determine Geometric Isomers
- For the double bond (C2=C3), we can have:
- **Cis Isomer**: The NH₂ group and CH₃ group are on the same side of the double bond.
- **Trans Isomer**: The NH₂ group and CH₃ group are on opposite sides of the double bond.

### Step 4: Count Stereoisomers
1. **Cis Isomer**:
- The chiral center (C4) can exist in two configurations (D and L forms).
- Therefore, for the cis isomer, we have 2 stereoisomers (D and L).

2. **Trans Isomer**:
- Similarly, the trans isomer also has the chiral center (C4) that can exist in two configurations (D and L forms).
- Therefore, for the trans isomer, we also have 2 stereoisomers (D and L).

### Step 5: Total Stereoisomers
Adding the stereoisomers from both the cis and trans forms:
- Cis Isomers: 2 (D and L)
- Trans Isomers: 2 (D and L)

Total stereoisomers = 2 (cis) + 2 (trans) = 4 stereoisomers.

### Final Answer
The total number of stereoisomers for the compound CH₃-CH=CH-CH(NH₂)-CH₃ is **4**.

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