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A man weighs 'W' on the surface of the e...

A man weighs 'W' on the surface of the earth and his weight at a height 'R' from surface of the earth is (`R` is Radius of the earth )

A

W

B

`W/2`

C

`W/4`

D

`W/8`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the weight of a man at a height equal to the radius of the Earth, we can follow these steps: ### Step 1: Understand the weight on the surface of the Earth The weight of the man on the surface of the Earth is given as \( W \). This weight can be expressed as: \[ W = mg \] where \( m \) is the mass of the man and \( g \) is the acceleration due to gravity on the surface of the Earth. ### Step 2: Determine the height above the Earth's surface The problem states that the man is at a height \( R \) from the surface of the Earth, where \( R \) is the radius of the Earth. Therefore, the total distance from the center of the Earth to the man is: \[ h = R + R = 2R \] ### Step 3: Use the formula for gravitational acceleration at height The gravitational acceleration \( g' \) at a height \( h \) from the surface of the Earth is given by the formula: \[ g' = \frac{g R^2}{(R + h)^2} \] Substituting \( h = R \): \[ g' = \frac{g R^2}{(R + R)^2} = \frac{g R^2}{(2R)^2} = \frac{g R^2}{4R^2} = \frac{g}{4} \] ### Step 4: Calculate the weight at the height \( R \) The weight of the man at this height \( W' \) can be calculated using the new gravitational acceleration \( g' \): \[ W' = mg' = m \left(\frac{g}{4}\right) = \frac{mg}{4} \] Since \( W = mg \), we can substitute: \[ W' = \frac{W}{4} \] ### Step 5: Conclusion Thus, the weight of the man at a height \( R \) from the surface of the Earth is: \[ W' = \frac{W}{4} \] ### Final Answer The man's weight at a height \( R \) from the surface of the Earth is \( \frac{W}{4} \). ---
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