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When a piece of metal is illuminated by monochromatic light of wavelength `lambda,` then stopping potential is `3V_(s)`. When the same surface is illuminated by the light of wavelength `2lambda`, then stopping potential becomes `V_(s)`. The value of threshold wavelength for photoelectric emission will be

A

`4 lambda`

B

`8 lambda`

C

`4/3 lambda`

D

`6 lambda`

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The correct Answer is:
A
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