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An alpha nucleus of energy (1)/(2)mv^(2)...

An alpha nucleus of energy `(1)/(2)mv^(2)` bomobards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

A

`v^2`

B

`1//m`

C

`1//Ze`

D

`1//v^2`

Text Solution

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The correct Answer is:
B
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