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In the cyclotron, as radius of the circu...

In the cyclotron, as radius of the circular path of the charged particle increase (`omega` = angular velocity, v = linear velocity)

A

Both `omega and upsilon` increase

B

only `omega` increase, `upsilon` remains constant

C

only `upsilon` increases , `omega` remains constant

D

`upsilon` increases, `omega` decreases

Text Solution

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The correct Answer is:
To solve the problem regarding the behavior of angular velocity and linear velocity in a cyclotron as the radius of the circular path of a charged particle increases, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Cyclotron**: A cyclotron is a device that accelerates charged particles using a magnetic field. The charged particle moves in a circular path due to the Lorentz force exerted by the magnetic field. 2. **Identify the Key Relationships**: - The linear velocity \( v \) of the charged particle in a cyclotron is given by the formula: \[ v = \frac{Bqr}{m} \] where: - \( B \) = magnetic field strength - \( q \) = charge of the particle - \( r \) = radius of the circular path - \( m \) = mass of the particle - The angular velocity \( \omega \) is given by: \[ \omega = \frac{v}{r} \] 3. **Analyzing the Effect of Increasing Radius**: - If the radius \( r \) increases, we can analyze how it affects \( v \) and \( \omega \). - From the equation for linear velocity: \[ v = \frac{Bqr}{m} \] Since \( B \), \( q \), and \( m \) are constants, an increase in \( r \) will lead to a proportional increase in \( v \). Thus, \( v \) increases as \( r \) increases. 4. **Analyzing Angular Velocity**: - Now, substituting the expression for \( v \) into the equation for \( \omega \): \[ \omega = \frac{v}{r} = \frac{Bqr/m}{r} = \frac{Bq}{m} \] - Here, \( B \), \( q \), and \( m \) are constants, meaning that \( \omega \) does not depend on \( r \). Therefore, \( \omega \) remains constant even as \( r \) increases. 5. **Conclusion**: - As the radius \( r \) of the circular path increases, the linear velocity \( v \) increases, while the angular velocity \( \omega \) remains constant. ### Final Answer: - Linear velocity \( v \) increases. - Angular velocity \( \omega \) remains constant.
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