Home
Class 12
PHYSICS
When a Daniel cell is connected in the s...

When a Daniel cell is connected in the secondary circuit of a potentiometer, the balancing length is found to be 540 cm. If the balancing length becomes 500 cm when the cell is short - circuited with `1Omega`, the internal resistance of the cell `("in " Omega)` is

A

`0.08 Omega`

B

`0.04 Omega`

C

`1.08 Omega`

D

`1.45 Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

When 6 identical cells of no internal resistance are connected in series in the secondarycircuit of a potentio meter, the balancing lengths is .l., balancing length becomes 1/3 when some cells are connected wrongly, the number of cells connected wrongly are

In a potentiometer the balancing with a cell is at length of 220cm. On shunting the cell with a resistance of 3Omega balance length becomes 130cm. What is the internal resistance of this cell.

For the given circuit, If internal resistance of cell is 1.5 Omega , then

In an experiment to determine the internal resistance of a cell with potentiometer, the balancing length is 165 cm. When a resistance of 5 ohm is joined in parallel with the cell the balancing length is 150 cm. The internal resistance of cell is

The adjoining figure shows the connection of potentiometer experiment to determine internal resistance of a leclanche cell. When the cell is an open circuit the balancing length of the potentiometer wire is 3 .4m and on closing the key K_2 the balancing length becomes 17.m. If the resistance R through which current is dream is 10 Omega then the internal resistance of the cell is:

In a potentiometer experiment the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of 2Omega , the balancing length becomes 120 cm.The internal resistance of the cell is

In an experiment to measure the internal resistance of a cell by a potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 5 Omega resistance and is at a length of 3 m when the cell is shunted by a 10 Omega resistance, the internal resistance of the cell is then

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 4Omega resistance and at 3 m when cell is shunted by a 8Omega resistance. The internal resistance of cell is -

Two cells of E.M.F. E_(1) and E_(2)(E_(2)gtE_(1)) are connected in series in the secondary circuit of a potentiometer experiment for determination of E.M.F. The balancing length is found to be 825 cm. Now when the terminals to cell E_(1) are reversed, then the balancing length is found to be 225 cm. The ratio of E_(1) and E_(2) is

A battery is connected to a potentiometer and a balance point is obtained at 84 cm along the wire. When its terminals are connected by a 5 Omega resistor, the balance point changes to 70 cm . Calculate the internal resistance of the cell.