Home
Class 12
PHYSICS
In each heartbeat , a heart pumps 80 ml ...

In each heartbeat , a heart pumps 80 ml of blood at an average pressure of 100 mm of Hg. Assuming 60 heartbeat per second , the Power output of the heart is `(rho_(Hg)Hg = 13.6 xx 10^3 kg m ^(-3)) (g = 9.8 m s^(-2) )`

A

1 W

B

2.75 W

C

1.06 W

D

0.5 W

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

In each heart beat, a heart pumps 80 ml blood at an average pressure of 100 ml of Hg. What will be the power output of the herat? (Assume 60 heart beat per minute

A human heart pumps 50 cc of blood per heart besat at a pressure of 1.5 m of water. If the heart beats are 75 per minute then average pumping power of heart ( g = 10 m/s^2 )

Convert 1 mm of Hg into pascal. Take density of Hg=13.6xx10^(3)kg m^(-3) and g=9.8 ms^(-2) .

The upper blood pressure of a patient is 160 cm of Hg whereas the normal blood pressure should be 120 cm of Hg. Calculate the extra pressure generated by the heart in S.I. unit . Take density of Hg=13600 kg m^(-3) and g=9.8 ms^(-2) .

The heart of a man pumps 5 liters of blood through the arteries per minute at a pressure of 150 mm of mercury. If the density of mercury be 13.6xx10^(3) kg//m^(3) and g=10 m//s^(2) then the power of heat in watt is :

Find the pressure exerted below a column of water, open to the atmosphere, at depth (i) 5 m (ii) 20 m (Given, density of water = 1 xx 10^(3)"kg m"^(-3), g = 10 m s^(-2) )

An engine can pump 30,000 L of water to a vertical height of 45 m in 10 min. Calculate the work done by the machine and the power. (Density of water = 10^3 kg//m^3, 1000 L - 1 m^3 , g = 9.8 ms^(-2) )

The average human heart forces four litre of blood per minute through arteries a pressure of 125 mm. If the density of blood is 1.03xx10^(3)kg//m^(3) then the power of heart is :

A square plate of side 10 m is placed horizontally 1 m below the surface of water. The atmospheric pressure is 1.013xx10^(5)Nm^(-2) . Calculate the total thrust on the plate. (Density of water rho=10^(3)kg m^(-3), g=9.8ms^(-2))

At what depth below the surface of water will pressure be equal to twice the atmospheric pressure ? The atmospheric pressure is 10N cm^(-2) , density of water is 10^(3)kg m^(-3) and g=9.8 ms^(-2) .