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1 mole of a monoatomic gas is taken from...

1 mole of a monoatomic gas is taken from a point A to another point B along the path ACB. The initial temperature at A is `T_0`. The heat absorbed by the gas in the process `A to C to B` is `("nRT"_(0))/2` Find is :

A

`(11RT_(0))/(2)`

B

`(7RT_(0))/(2)`

C

`(5RT_(0))/(2)`

D

`(13RT_(0))/(2)`

Text Solution

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The correct Answer is:
A
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