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In a vernier callipers, one main scale d...

In a vernier callipers, one main scale division is x cm and n divisions of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is :-

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To find the least count of the vernier callipers, we will follow these steps: ### Step 1: Understand the Definitions - The least count (LC) of a measuring instrument is the smallest value that can be measured accurately with that instrument. - In a vernier calliper, the least count can be calculated using the formula: \[ \text{Least Count (LC)} = \text{One Main Scale Division (MSD)} - \text{One Vernier Scale Division (VSD)} \] ### Step 2: Identify the Given Values - Let the value of one main scale division (MSD) be \( x \) cm. - According to the problem, \( n \) divisions of the vernier scale coincide with \( n-1 \) divisions of the main scale. ### Step 3: Calculate the Vernier Scale Division - Since \( n \) divisions of the vernier scale coincide with \( n-1 \) divisions of the main scale, we can express the vernier scale division (VSD) as: \[ \text{VSD} = \frac{(n-1) \text{ MSD}}{n} \] - Substituting the value of MSD: \[ \text{VSD} = \frac{(n-1) x}{n} \] ### Step 4: Substitute into the Least Count Formula - Now, substituting the values of MSD and VSD into the least count formula: \[ \text{LC} = \text{MSD} - \text{VSD} \] \[ \text{LC} = x - \frac{(n-1) x}{n} \] ### Step 5: Simplify the Expression - To simplify the expression: \[ \text{LC} = x - \frac{(n-1)x}{n} = x \left(1 - \frac{(n-1)}{n}\right) \] - This can be simplified further: \[ \text{LC} = x \left(\frac{n}{n} - \frac{(n-1)}{n}\right) = x \left(\frac{n - (n-1)}{n}\right) = x \left(\frac{1}{n}\right) \] ### Step 6: Final Result - Therefore, the least count of the vernier callipers is: \[ \text{LC} = \frac{x}{n} \text{ cm} \]
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