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Turpentine oil is flowing through a tube...

Turpentine oil is flowing through a tube of length `L` and radius `r`. The pressure difference between the two ends of the tube is `p` , the viscosity of the coil is given by `eta = (p (r^(2) - x^(2)))/(4 vL)`, where `v` is the velocity of oil at a distance `x` from the axis of the tube. From this relation, the dimensions of viscosity `eta` are

A

`4pi etalV_(0)`

B

`2pietalV_(0)`

C

`pietalV_(0)`

D

`(2)/(3)pi etalV_(0)`

Text Solution

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The correct Answer is:
A
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