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The equation of the circumcricle of the ...

The equation of the circumcricle of the `x^(2)-8x+12=0 and y^(2)-14y+45=0` is

A

`x^(2)+y^(2)-4x-7y+57=0`

B

`x^(2)+y^(2)-8x-14y+57=0`

C

`x^(2)+y^(2)-8x-|14y+5|=0`

D

`2x^(2)+y^(2)-8x-14y+57=0`

Text Solution

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The correct Answer is:
To find the equation of the circumcircle of the curves given by the equations \(x^2 - 8x + 12 = 0\) and \(y^2 - 14y + 45 = 0\), we will follow these steps: ### Step 1: Factor the first equation \(x^2 - 8x + 12 = 0\) We can factor this quadratic equation: \[ x^2 - 8x + 12 = (x - 6)(x - 2) = 0 \] From this, we find the roots: \[ x = 6 \quad \text{and} \quad x = 2 \] ### Step 2: Factor the second equation \(y^2 - 14y + 45 = 0\) Next, we factor the second quadratic equation: \[ y^2 - 14y + 45 = (y - 9)(y - 5) = 0 \] From this, we find the roots: \[ y = 9 \quad \text{and} \quad y = 5 \] ### Step 3: Identify the points The points of intersection (roots) from the equations are: 1. \( (2, 5) \) 2. \( (2, 9) \) 3. \( (6, 5) \) 4. \( (6, 9) \) ### Step 4: Determine the center and radius of the circumcircle The circumcircle will have its center at the midpoint of the line segment connecting the points \( (2, 5) \) and \( (6, 9) \). **Midpoint Calculation:** \[ \text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{2 + 6}{2}, \frac{5 + 9}{2} \right) = \left( 4, 7 \right) \] ### Step 5: Calculate the radius The radius is the distance from the center \( (4, 7) \) to one of the points, say \( (2, 5) \). **Distance Calculation:** \[ r = \sqrt{(4 - 2)^2 + (7 - 5)^2} = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} \] ### Step 6: Write the equation of the circumcircle The general equation of a circle is given by: \[ (x - h)^2 + (y - k)^2 = r^2 \] Substituting \(h = 4\), \(k = 7\), and \(r = 2\sqrt{2}\): \[ (x - 4)^2 + (y - 7)^2 = (2\sqrt{2})^2 \] This simplifies to: \[ (x - 4)^2 + (y - 7)^2 = 8 \] ### Step 7: Expand the equation Expanding the equation gives: \[ (x^2 - 8x + 16) + (y^2 - 14y + 49) = 8 \] Combining terms results in: \[ x^2 + y^2 - 8x - 14y + 57 = 0 \] ### Final Answer Thus, the equation of the circumcircle is: \[ x^2 + y^2 - 8x - 14y + 57 = 0 \] ---
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