In the majority of the flowering plants, female gametophytes having eight nuclei is

Options

A. tetrasporic
B. monosporic
C. bisporic
D. trisporic

Answer

To solve the question regarding the female gametophytes having eight nuclei in flowering plants, we can break down the information step by step.

### Step-by-Step Solution:

1. **Understanding Female Gametophyte Development**:
- In flowering plants, the development of the female gametophyte occurs from the megaspore. The process involves several divisions and can be classified into different types based on the number of functional megaspores produced.

2. **Identifying the Types of Development**:
- The types of development mentioned in the options are:
- **Monosporic**: One functional megaspore is produced.
- **Bisporic**: Two functional megaspores are produced.
- **Tetrasporic**: Four functional megaspores are produced, but they remain in one cell.
- **Trisporic**: This type does not exist as it would require an odd number of divisions which is not feasible.

3. **Focusing on Monosporic Development**:
- In monosporic development, one functional megaspore undergoes mitotic divisions. The process is as follows:
- The single functional megaspore divides mitotically to form two nuclei.
- These nuclei then divide again, leading to four nuclei.
- A final mitotic division results in eight nuclei.

4. **Formation of the Female Gametophyte**:
- After reaching the eight-nuclei stage, cell walls are formed around six of these nuclei, creating the typical structure of the female gametophyte.
- The remaining two nuclei become the polar nuclei, which fuse to form the central cell.

5. **Conclusion**:
- Based on the explanation, the correct answer to the question is that in the majority of flowering plants, the female gametophytes with eight nuclei are developed through **monosporic** development.

### Final Answer:
**Monosporic development** (Option B).