On reaction of ozone with hydrogen peroxide if we start with one volume of ozone. How many volumes of oxygen will form?

Options

A. 1 volume
B. 0.5 volume
C. 1.5 volume
D. 2 volume

Answer

To solve the problem of how many volumes of oxygen will form from the reaction of ozone (O₃) with hydrogen peroxide (H₂O₂), we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between ozone and hydrogen peroxide can be represented as:
\[ O_3 + H_2O_2 \rightarrow H_2O + 2O_2 \]

### Step 2: Analyze the stoichiometry of the reaction
From the balanced equation, we can see that:
- 1 mole of ozone (O₃) reacts with 1 mole of hydrogen peroxide (H₂O₂) to produce 1 mole of water (H₂O) and 2 moles of oxygen (O₂).

### Step 3: Determine the volume relationship
According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain an equal number of molecules. Therefore, the volume ratio will be the same as the mole ratio.

From the balanced equation:
- 1 volume of O₃ produces 2 volumes of O₂.

### Step 4: Calculate the volumes
If we start with 1 volume of ozone (O₃), the reaction will produce:
- 2 volumes of oxygen (O₂).

### Conclusion
Thus, if we start with one volume of ozone, we will form 2 volumes of oxygen.

### Final Answer
The answer is 2 volumes of oxygen.

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