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The maximum height attained by a project...

The maximum height attained by a projectile when thrown at an angle `theta` with the horizontal is found to be half the horizontal range. Then `theta` is equal to

A

`tan^(-1)(2)`

B

`pi/6`

C

`pi/4`

D

`tan^(-1)(1/2)`

Text Solution

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The correct Answer is:
A
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