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A copper rod of length l(0) at 0^(@)C is...

A copper rod of length `l_(0)` at `0^(@)`C is placed on smooth surface. Now, the rod is heated upto `100^(@)`C. Find the longitudinal strain developed.
(`alpha`=coefficient of linear expansion)

A

`(100 - alpha)/(l_0 + 100 l_0 alpha)`

B

`100 alpha`

C

Zero

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the longitudinal strain developed in a copper rod when it is heated from \(0^\circ C\) to \(100^\circ C\), we can follow these steps: ### Step 1: Understand the concept of linear expansion When a material is heated, it expands. The change in length (\(\Delta L\)) of a rod due to temperature change can be expressed using the formula: \[ \Delta L = L_0 \cdot \alpha \cdot \Delta T \] where: - \(L_0\) = original length of the rod - \(\alpha\) = coefficient of linear expansion - \(\Delta T\) = change in temperature ### Step 2: Calculate the change in temperature The change in temperature (\(\Delta T\)) when the rod is heated from \(0^\circ C\) to \(100^\circ C\) is: \[ \Delta T = 100^\circ C - 0^\circ C = 100^\circ C \] ### Step 3: Substitute the values into the linear expansion formula Now substituting the values into the linear expansion formula: \[ \Delta L = L_0 \cdot \alpha \cdot 100 \] ### Step 4: Define longitudinal strain Longitudinal strain (\(\epsilon\)) is defined as the ratio of the change in length to the original length: \[ \epsilon = \frac{\Delta L}{L_0} \] ### Step 5: Substitute \(\Delta L\) into the strain formula Now substituting \(\Delta L\) into the strain formula: \[ \epsilon = \frac{L_0 \cdot \alpha \cdot 100}{L_0} \] ### Step 6: Simplify the expression The \(L_0\) terms cancel out: \[ \epsilon = 100 \cdot \alpha \] ### Final Result Thus, the longitudinal strain developed in the copper rod when heated from \(0^\circ C\) to \(100^\circ C\) is: \[ \epsilon = 100 \alpha \] ---
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