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The spectral emissive power E(lambda) fo...

The spectral emissive power `E_(lambda)` for a body at temperature `T_(1)` is plotted against the wavelength (see figure) and area under the curve is found to be A. At a different temperature `T_(2)` the area is found to be 9A. Then `lambda_(1)//lambda_(2)=`

A

3

B

`1/3`

C

`1/(sqrt3)`

D

`sqrt(3)`

Text Solution

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The correct Answer is:
D
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