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With a monochromatic light, the fringe-w...

With a monochromatic light, the fringe-width obtained in a Young’s double slit experiment is 0.133 cm. The whole set- up is immersed in water of refractive index 1.33, then the new fringe-width is

A

Does not change

B

1.0 mm

C

2.0 mm

D

2.69 mm

Text Solution

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The correct Answer is:
To solve the problem of finding the new fringe width when the Young's double slit experiment setup is immersed in water, we can follow these steps: ### Step 1: Understand the formula for fringe width The fringe width (β) in a Young's double slit experiment is given by the formula: \[ \beta = \frac{\lambda D}{d} \] where: - \( \lambda \) = wavelength of the light - \( D \) = distance from the slits to the screen - \( d \) = distance between the slits ### Step 2: Determine the effect of immersion in water When the setup is immersed in water, the wavelength of the light changes. The new wavelength (\( \lambda' \)) in a medium with refractive index \( \mu \) is given by: \[ \lambda' = \frac{\lambda}{\mu} \] In this case, the refractive index of water is given as \( \mu = 1.33 \). ### Step 3: Express the new fringe width The new fringe width (\( \beta' \)) when the setup is in water can be expressed as: \[ \beta' = \frac{\lambda' D}{d} = \frac{\left(\frac{\lambda}{\mu}\right) D}{d} = \frac{\beta}{\mu} \] This shows that the new fringe width is the original fringe width divided by the refractive index. ### Step 4: Substitute the known values We know from the problem that the original fringe width \( \beta = 0.133 \, \text{cm} \) and the refractive index \( \mu = 1.33 \). Thus, we can substitute these values into the equation: \[ \beta' = \frac{0.133 \, \text{cm}}{1.33} \] ### Step 5: Calculate the new fringe width Now, performing the calculation: \[ \beta' = \frac{0.133}{1.33} \approx 0.1 \, \text{cm} \] ### Step 6: Convert to mm if necessary Since the answer may need to be in millimeters, we convert \( 0.1 \, \text{cm} \) to mm: \[ 0.1 \, \text{cm} = 1 \, \text{mm} \] ### Final Answer Thus, the new fringe width when the setup is immersed in water is: \[ \beta' = 1 \, \text{mm} \]
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