A magnet of magnetic moment 10 `Am^(2)` has magnetic length 5 cm.The strength of magnet is

Options

A. 200 A m
B. 100 Am
C. 300 Am
D. 50 Am

Answer

To solve the problem of finding the strength of a magnet given its magnetic moment and magnetic length, we can follow these steps:

### Step 1: Identify the given values
- Magnetic moment (M) = 10 Am²
- Magnetic length (L) = 5 cm

### Step 2: Convert the magnetic length from centimeters to meters
Since the standard unit for length in the International System of Units (SI) is meters, we need to convert 5 cm to meters:
\[ L = 5 \text{ cm} = \frac{5}{100} \text{ m} = 0.05 \text{ m} \]

### Step 3: Use the formula for magnetic strength
The strength of the magnet (P) can be calculated using the formula:
\[ P = \frac{M}{L} \]
where:
- P = strength of the magnet (in Am)
- M = magnetic moment (in Am²)
- L = magnetic length (in m)

### Step 4: Substitute the values into the formula
Now, substituting the values we have:
\[ P = \frac{10 \text{ Am}^2}{0.05 \text{ m}} \]

### Step 5: Calculate the strength of the magnet
Perform the calculation:
\[ P = \frac{10}{0.05} = 10 \times 20 = 200 \text{ Am} \]

### Conclusion
The strength of the magnet is:
\[ P = 200 \text{ Am} \]