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Magnetic flux passing through a coil is ...

Magnetic flux passing through a coil is initially `4xx 10^-4` Wb. It reduces to 10% of its original value in t second. If the emf induced is 0.72 mV then t in second is

A

`0.3`

B

`0.4`

C

`0.5`

D

`0.6`

Text Solution

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The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Identify the initial magnetic flux The initial magnetic flux (\( \Phi_0 \)) is given as: \[ \Phi_0 = 4 \times 10^{-4} \, \text{Wb} \] ### Step 2: Calculate the final magnetic flux The final magnetic flux (\( \Phi \)) is 10% of the initial value. Therefore: \[ \Phi = 0.1 \times \Phi_0 = 0.1 \times (4 \times 10^{-4}) = 4 \times 10^{-5} \, \text{Wb} \] ### Step 3: Calculate the change in magnetic flux The change in magnetic flux (\( \Delta \Phi \)) can be calculated as: \[ \Delta \Phi = \Phi_0 - \Phi = (4 \times 10^{-4}) - (4 \times 10^{-5}) = 4 \times 10^{-4} - 0.4 \times 10^{-4} = 3.6 \times 10^{-4} \, \text{Wb} \] ### Step 4: Use the formula for induced EMF The induced electromotive force (EMF) is given as: \[ \text{EMF} = \frac{\Delta \Phi}{\Delta t} \] Given that the EMF is \( 0.72 \, \text{mV} = 0.72 \times 10^{-3} \, \text{V} \), we can set up the equation: \[ 0.72 \times 10^{-3} = \frac{3.6 \times 10^{-4}}{t} \] ### Step 5: Solve for time \( t \) Rearranging the equation to solve for \( t \): \[ t = \frac{3.6 \times 10^{-4}}{0.72 \times 10^{-3}} \] Calculating this gives: \[ t = \frac{3.6}{0.72} \times 10^{-1} = 5 \times 10^{-1} = 0.5 \, \text{s} \] ### Conclusion Thus, the time \( t \) is: \[ \boxed{0.5 \, \text{s}} \]
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