Home
Class 12
PHYSICS
A simple harmonic motion is represented ...

A simple harmonic motion is represented by `x(t) = sin^2 omegat - 2 cos^(2) omegat`. The angular frequency of oscillation is given by

A

`omega`

B

`2 omega`

C

`4 omega`

D

`omega/2`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

The equation of a damped simple harmonic motion is m(d^2x)/(dt^2)+b(dx)/(dt)+kx=0 . Then the angular frequency of oscillation is

The position and velocity of a particle executing simple harmonic motion at t = 0 are given by 3 cm and 8 cm s^(-1) respectively . If the angular frequency of the particle is 2 "rad s" ^(-1) , then the amplitude of oscillation (in cm) is

A particle executes simple harmonic motion and is located at x = a , b at times t_(0),2t_(0) and3t_(0) respectively. The frequency of the oscillation is :

What is the phase difference between two simple harmonic motions represented by x_(1)=A"sin"(omegat+(pi)/(6)) and x_(2)=A "cos"omegat ?

Two simple harmonic motions are given by y _(1) = 5 sin ( omegat- pi //3). y_(2) = 5 ( sin omegat+ sqrt(3) cos omegat) . Ratio of their amplitudes is

The motion of a particle is given by x=A sin omegat+Bcos omegat . The motion of the particle is

The displacement of a particle is represented by the equation y=sin^(3)omegat . The motion is