lf (x,y) be a point equidistant from the points (7,5),(4,3).then show that 6x+4y=49.

Consider a plane which is equidistant from the points (1,2,1) and (3,4,7). Find the equation of the above plane.

Find the point on the x-axis which equidistant from the points (7,6) and (3,4)

Find a point on the x-axis,which is equidistant from the points (7,6) and (3,4)

The locus of the point (x,y) which is equidistant from the points (a + b, b -a ) and (a-b, a +b ) is :

Find the distance of the point (- 2,3) from the line x - y = 5.

Find the distance of the point (3,-5) from the line 3x-4y-26=0

(b)Find the distance of the point (3,-3) from the line 3x-4y-26=0 .

Find the length and foot of the perpendicular from the point (7,14,5) to the plane 2x+4 y-z=2 .

Find the co-ordinates of the foot at the perpendicular from the point (-1,3) to the line 3x - 4y - 16 = 0

The sum of the minimum distance and the maximum distance from the point (4, -3) to the circle x^(2) + y^(2) + 4x - 10y - 7 = 0 is a)20 b)12 c)10 d)16