If p(x) is divided by (2x-1),the remainder got is given by `[p(1/2), p(-1/2), p(-2), p(2)]`.

If p(x) is divided by (x+1), the remainder got is given by [p(1/2), p(-1/2), p(-1), p(1)] .

The quotient is x^2-5x+6 when the polynomial p(x) is divided by (x-1), and the remainder is 7.Then:- p(x)=(.....) (……...)+7.Complete it.

The quotient is x^2-5x+6 when the polynomial p(x) is divided by (x-1), and the remainder is 7.Then:- Find P(2).

Find P^(-1) , if it exists, given P = [(10,-2),(-5,1)]

Write the product (x-1) xx (x+1) Find the product of (x-1),(x+1),(x+ 2) If the product is p(x), find p(1),p(-1),p(-2) Write the solution of the equation p(x)=0.

If P(x)= x^3- 6x^2 + 11x-1 then find: p(2)

If P(x)= x^3- 6x^2 + 11x-1 then find: p(1)

If P(x)= x^3- 6x^2 + 11x-1 then find: p(3)

If P(x)=2x^2-3x+1 ,then What number is P(1) ?