The relative decrease in the vapour pressure of an aqueous solution containing 2 mol `[Cu(NH)_3CI]Cl` in 3 mol `H_2O` is 0.50. On reaction with `AgNO_3,` this solution will form a)1 mol AgCl b)0.25 mol AgCl c)2 mol AgCl d)0.40 mol AgCl

Options

A. 1 mol AgCl
B. 0.25 mol AgCl
C. 2 mol AgCl
D. 0.40 mol AgCl

Answer

A

Explanation

`(triangle P)/(P^@)=0.50=(n_(1)i)/(n_(1)i+n_(2))`
degree of dissociation `alpha=(i-1)/1=0.5`
`0.50=(2i)/(2i+3)" i=1.5-=1+x, x=0.5"`
Hence, 2 mol complex produce 1 mol unionised complex, 1 mol `Cl^(-)` ion and 1 mol cation. 1 mol Cl ion produces 1 mol AgCl.