If `A=[[alpha ,beta],[ gamma , -alpha]]` is such that `A^2=I`, then A) `1+alpha^2+beta gamma=0` B) `1-alpha^2+beta gamma=0` C)`1-alpha^2-beta gamma=0^`D)`1+alpha^2-beta gamma=0`

If a, b and c are in geometric progression and the roots of the equations ax^(2)+2bx+c=0 are alpha and beta and those cx^(2)+2bx+a=0 are gamma and delta , then : a) alpha ne beta ne gamma ne delta b) alpha ne beta and gamma ne delta c) alpha=abeta=cgamma=cdelta d) alpha=beta and gamma ne delta

Let A=[(0,2beta,gamma),(alpha,beta,-gamma),(alpha,-beta,gamma)] be 3xx3 matrix Find A^T

If alpha, beta, gamma are the roots of the equation x^(3)+4x+1=0 , then find the value of (alpha+beta)^(-1) +(beta +gamma)^(-1) + (gamma+ alpha)^(-1)

Let A=[(0,2beta,gamma),(alpha,beta,-gamma),(alpha,-beta,gamma)] be 3xx3 matrix If A^T.A=6I, then alpha,beta and gamma is -

If cos alpha + 2cos beta+ 3 cos gamma = 0, sin alpha + 2sin beta +3 sin gamma= 0 and alpha + beta + gamma= pi , then sin 3alpha + 8 sin 3 beta + 27 sin 3 gamma =

If alpha+beta =pi//2andbeta+gamma=alpha , then tanalpha equals

If A(alpha, beta) = [(cos alpha, sin alpha, 0),(- sin alpha, cos alpha, 0),(0,0,e^beta)] then A(alpha, beta)^(-1) is equal to a) A(-alpha, -beta) b) A(-alpha,beta) c) A(alpha, - beta) d) A(alpha, beta)