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Find the points of intersection of the parabola `y^2=8x` and the line y=2x.

Answer

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Knowledge Check

  • If a ne 0 and the line 2bx + 3cy + 4d = 0 passes through the points of intersection of the parabolas y^(2) = 4ax and x^(2) = 4ax ,then

    A
    `d^(2) + (2b + 3c)^(2) = 0`
    B
    ` d^(2) + (3b+ 2c) ^(2) = 0`
    C
    ` d^(2) + (2b - 3c) ^(2) = 0`
    D
    ` d^(2) + ( 3b - 2c) ^(2) = 0`

  • The angle between the lines joining the origin to the points of intersection of the line sqrt3x+y=2 and the curve y^2 –x^2 = 4 is

    A
    `tan^(-1)(2//sqrt3)`
    B
    `pi//6`
    C
    `tan^(-1) (sqrt3//2)`
    D
    `pi//2`

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