`e^x tan y d x+(1-e^x) (sec ^2 y) d y=0`

Find the general solution of the following differential equation e^x tan y dx + (1-e^x)sec^2 y dy =0

Consider the differential equation 3e^xtan y dx-(1+e^x)sec^2 y dy=0 Order of the differential equation is ....

solve y d x+x log (y/x) d y-2 x d y=0

Solve the differential equation y e^(x/y) d x=(x e^(x/y)+y^2) d y(y ne 0)

Which of the following is a homogeneous differential equation? (4 x+6 y+5) d y-(3 y+2 x+4) d x=0 x y d x-(x^3+y^3) d y=0 (x^3+2 y^2) d x+2 x y d y=0 y^2 d x+(x^2-x y-y^2) d y=0

Choose the correct answer. The general solution of a differential equation e^x dy + (y e^x + 2x) dx = 0 is... a) x e^x + x^2 = c b) x e^y + y^2 = c c) x e^y + y^2 = c d) y e^x + x^2 = c

The area between the curves y = xe ^(x) and y = xe ^(-x) and the line x=1, is a) 2 (e + (1)/(e)) sq unit b)0 sq unit c) 2/e sq unit d) 2 (e - (1)/(e)) sq unit

The general solution of the differential equation (dy)/(dx) = e^(y) (e^(x) + e^(-x) + 2x) is a) e^(-y) = e^(x) - e^(-x) + x^(2) + C b) e^(-y) = e^(-x) - e^(x) - x^(2) + C c) e^(-y) = -e^(-x) - e^(x) - x^(2) + C d) e^(y) = e^(-x) + e^(x) + x^(2) + C