Find the equation of a curve passing through the point `(-2,3)`, given that the slope of the tangent to the curve at any point `(x, y)` is `(2 x)/y^2`

Find the equation of a curve passing through the origin given that the slope of the tangent to the curve at any point (x,y) is equal to the sum of the coordinate of the point.

Find the equation of a curve passing through the point (0,1). If the slope of the tangent to the curve at any point (x,y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate of that point.

Find the slope of the tangent to the curve y=(x-2)^2 at x=1

The slope of the tangent to the curve y=x^3-1 at x=2 is………

Find the equation of a curve passing through the point (0,2) given that the sum of the coordinates of any point on the curve exceeds the magnitude of the slope of the tangent to the curve at that point by 5.

Slope of the tangent to the curve y=3x^2+2sinx at x=0 is

Find the slope of the tangent to the curve 'y=x^3-x' at 'x=2'.

Find the equation of the tangent to the curve y=3x^2 at (1,1)

Find the slope of tangent line to the curve y=x^2-2x+1