Consider `(1+y^2)dx=(tan^-1y-x)dy` Express the equation in the form `dx/dy+Px=Q`

Consider (1+y^2)dx=(tan^-1y-x)dy Solve the given equation.

Consider (1+y^2)dx=(tan^-1y-x)dy Find the integrating factor.

Consider xlogxdy/dx+y=2/xlogx , x>0 Express the equation in the form dy/dx+Py=Q .

Given y dx-xdy+(logx)dx=0 Express the given equation in the form dy/dx+Py=Q .

Consider the DE xdy-ydx=sqrt(x^2+y^2)dx Express it in the form dy/dx=F(x,y)

Consider the DE (x^2+y^2)dx=2xydy Write the DE in the form dy/dx=g[y/x]

Consider xdy/dx=y-xtan(y/x), Express dy/dx as a function of y/x.

Given (1+e^(x//y))dx+e^(x//y)(1-x/y)dy=0 Express the differential equation as dx/dy = A function of (x/y) .

Consider the equation. dy/dx+y=sinx Solve this equation.

Solve the DE (1+x^2)dy/dx+y=tan^-1x