Given the straight line `(x+5)/1=(y+3)/4=(z-6)/-9`. What are its direction rations?

Given the straight line (x+5)/1=(y+3)/4=(z-6)/-9 Obtain the equation of the straight line passing through (2,4,-1) and line parallel to the given line.

Consider the cartesian equation of the line (x-5)/3=(y+4)/7=(z-6)/2 Write the direction ratios of the line.

The cartestian equation of a line is (x-5)/3=(y+4)/7=(z-6)/2 . Write its vector form.

A unit vector parallel to the straight line (x-2)/(3) = ( 3 + y)/(-1) = (z -2)/(-4) is

Consider the Cartesian equation of line (x-3)/2=(y+1)/3=(z-5)/-2 Find its intersecting point with the plane 5x+2y-6z-7=0

Consider the pair of lines whose equations are . (x-2)/2=(y-1)/5=(z+3)/-3 and (x+1)/-1=(y-4)/8=(z-5)/4 Write the direction ratios of the lines.

If the straight lines (x - 2)/(1) = (y - 3)/(1) = (z - 4)/(0) and (x-1)/(k) = (y - 4)/(2) = (z - 5)/(1) are coplanar, then the value of k is

The point of intersection of the straight line (x-2)/(2) = (y-1)/(-3) = (z+2)/(1) with the plane x+3y - z + 1=0 is a) (3,-1,1) b) (-5,1,-1) c) (2,0,3) d) (4,-2,-1)

The vector equation of the straight line (x-2)/(1) = (y)/(-3) = (1-z)/(2) is