The angle between the straight line `r=(hati+2hatj+hatk)+lambda(hati-hatj+hatk)`
and the plane `r.(2hati-hatj+hatk)=4` is

Find the distance of the point (-1,-5,-10) from the point of intersecțion of the line vecr=(2 hati-hatj+2 hatk)+lambda(3 hati+4 hatj+ 2 hatk) and the plane vecr .(hati-hatj+hatk)=5

Consider the line vecr = (hati+2hatj-hatk)+lambda(2hati+hatj+4hatk) and the plane vecr . (hati-6hatj+hatk)+12=0 . Find a vector parallel to the line and a vector normal to the plane.