A straight line is passing through (3,8,3) and is parallel to the vector `3hati-hatj+k` Show that it is not coplanar with the lines `(x+3)/-3=(y+7)/2=(z-6)/4`

A straight line is passing through (3,8,3) and is parallel to the vector 3hati-hatj+k (i) Form its equation

A straight line is passing through (3,8,3) and is parallel to the vector 3hati-hatj+k .Calculate the shortest distance between these lines (x+3)/-3=(y+7)/2=(z-6)/4 .

A line passes through the point (3,-2,5) and parallel to the vector hati+2hatj+hatk What is the vector equation of the line?

The equation of the line which passes through the point (1,2,3) and parallel to the vector 3i+2j-2k is

Consider the plane passing through (2, 3, 5) and perpendiular to the vector 4hati+2hatj-3hatk Find the vector equation of the plane

Consider the plane passing through (2, 3, 5) and perpendiular to the vector 4hati+2hatj-3hatk Find the cartesian equation of the plane

If the lines passing through (3,y) and (2,7) are parallel to the line through (– 1, 4) and (0, 6) find the value of y

Find the vector equation of the line passing through (1,2,3) and parallel to the planes vecr .(hati-hatj+2 hatk)=5 and vecr .(3 hati+hatj+hatk)=6

Let OB=hati+2hatj+2hatkandOA=4hati+2hatj+2hatk . The distance of the point B from the straight line passing through A and parallel to the vector 2hati+3hatj+6hatk is a) (7sqrt(5))/(9) b) (5sqrt(7))/(9) c) (3sqrt(5))/(7) d) (9sqrt(5))/(7)