Find the equation of the plane containing the lines `(x-4)/1=(y-3)/4=(z-2)/5` and `(x-3)/1=(y-2)/-4=(z+3)/5`

Find the equation of the plane passing through the origin and containing the line (x-1)/(5)=(y-2)/(4)=(z-3)/(5)

Find the angles between the lines (x-2)/2=(y-1)/5=(z+3)/-3 and (x+2)/-1=(y-4)/8=(z-5)/4

Find the angle between the lines (x-3)/1=(y-1)/5=(z+3)/-3 and(x+1)/-1=(y-4)/8=(z-5)/4

Find the angle between the lines (x+3)/3=(y-1)/5=(z+3)/4 and (x+1)/1=(y-4)/1=(z-5)/2 .

If Q is the image of the point P (2,3,4) under the reflection in the plane x-2y+5z=6 then the equation of the line PQ is a) (x-2)/(-1)= (y-3)/2= (z-4)/5 b) (x-2)/(1)= (y-3)/(-2)= (z-4)/5 c) (x-2)/(-1)= (y-3)/(-2)= (z-4)/5 d) (x-2)/(1)= (y-3)/(2)= (z-4)/5